How do you graph # f(x)=1- cos 3x#?

1 Answer
Christian S.
Nov 5, 2015

#y=1-cos3x#

#y=Acos[B(x-C)]+D# ( A being amplitude, B being the period, C being the phase shift, and D being the vertical shift).

#y=cos[(3x)]-1#

Two things I can see immediately now that we reorganized the equation is that we have an amplitude of 1 and a vertical shift of -1 (down 1).

Now we will want to find the period using the equation for finding the period for cosines and sin #(2pi)/B#, so the period is #(2pi)/3#. We also see that there is no phase shift. Okay! We have everything we need to graph the equation now.

Amp: 1
Period: (2pi)/3
PS: none
VS: -1

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