How do you graph #f(x)=(1/2)x #?

1 Answer
Mar 2, 2018

This is a linear equation of the form:
#y = mx +b#

#m# is the slope and #b# is the y-intercept.

We can see that #m = 1/2# and #b = 0#, which means this a line with positive 1/2 slope that passes through the origin.

We place a point at the origin. Then we count 1 unit in the positive y direction (rise) and 2 units in the positive x direction (run) to arrive at point (2,1). If we go in the negative directions, we'd arrive at (-2, -1).

A similar process can be used to find more points until a line can be drawn.

graph{1/2x [-10, 10, -5, 5]}