How do you graph and solve |x+6| +8 >2?

1 Answer
Nov 24, 2015

See graph: This may not be the full answer as it was a long time ago that I did these. Hope what I have done helps!

Explanation:

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|x+6| " is always positive Within the 'absolute' x can take any including -6. At the point of x=-6 ; color(white)(...)|x+6| =0 and this is its minimum value. AS you are always adding 8 the minimum value is 0+8=8. Consequently all value of y >2.

Thus all the area above the plot is the feasible region.