How do you graph and solve $abs[2-x/2]-1<=1$ ?

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Answer 1 · 2018-05-16T09:24:40

$0<=x<=8$ or $x in[0,8]$

Add one to both sides to get:
$abs(2-x/2)<=1$

Now since we have $abs()$ we ca take the positive or negative of the function:

$2-x/2<=2$
$-x/2<=0$
$-x<=0$
$x>=0$

or

$x/2-2<=2$
$x/2<=4$
$x<=8$

Combining these gives us:
$0<=x<=8$ or $x in[0,8]$

How do you graph and solve abs[2-x/2]-1<=1 abs[2-x/2]-1<=1?