How do you graph and solve #6 abs(2x + 5) >66#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Bill Jorgensen Jun 11, 2018 #x>3# and #x< -8# #(oo,-3) uu (8,oo)# Explanation: #6 abs(2x + 5) >66# #abs(2x + 5) >11# #2x + 5 >11# #2x>6# #x>3# and #2x + 5 < -11# #2x < -16# #x< -8# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1562 views around the world You can reuse this answer Creative Commons License