How do you graph $| x + y | = 1$ $abs(x + y) = 1$ ?

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Answer 1 · 2015-07-10T18:54:56

This is two parallel lines of slope -1 with equations:

$x + y = 1$ $x+y=1$ and $x + y = - 1$ $x+y=-1$

If $| t | = 1$ $abs(t) = 1$ then $t = \pm 1$ $t = +-1$

graph{abs(x+y)=1 [-10, 10, -5, 5]}

How do you graph |x+y|=1abs(x + y) = 1?