How do you graph #8y> -4# on the coordinate plane?

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Answer 1 · 2018-02-09T20:50:15

See a solution process below:

Divide each side of the inequality by #color(red)(8)# to solve for #y# while keeping the inequality balanced:

#(8y)/color(red)(8) > -4/color(red)(8)#

#(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) > -1/2#

#y > -1/2#

To graph this we will draw a horizontal line at #-1/2# on the vertical axis.

The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.

We will shade above line because the inequality operator is a "greater than" operator:

graph{y > -1/2 [-4, 4, -2, 2]}