How do you graph #7y+4x>=7y+4#?

2 Answers
Apr 26, 2015

First graph the function 7y + 4x = 0 --> y = -4/7 x. This is a line passing at the origin and downward form Quadrant II to Quadrant IV.
Next, graph the line: y = -4/7. This is a horizontal line passing at point (0, -4/7).
To find the intersection of the 2 lines, solve the equation: 7y + 4x = 7y + 4 --> x = 1. The 2 lines meets at point (1, -4/7).
The answer for the inequality is the surface area between the 2 lines , within the interval (-infinity, 1). The 2 lines are also included in the solution set.

Apr 26, 2015

Simplify first. Subtracting #7y# from both sides yields:

#4x >= 4# so #x >= 1#.

Put a vertical line at #x=1#. The solution set is all points on or to the right of the line.

graph{x >= 1 [-3.22, 9.27, -2.67, 3.57]}