How do you graph $6 x - 2 y = 4$ $6x-2y=4$ by plotting points?

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How do you graph $6 x - 2 y = 4$ $6x-2y=4$ by plotting points?

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Answer 1 · 2017-07-19T04:49:05

Rearrange the equation to make $y$ $y$ the subject, and then substitute values of $x$ $x$ to get coordinates.

Explanation:

Rearrange the equation:

$- 2 y = 4 - 6 x$ $-2y = 4 - 6x$

$y = \frac{4 - 6 x}{- 2}$ $y = (4-6x)/-2$

Now input values of x and use the formula to find y.

For example, when $x = 0$ $x = 0$

$y = \frac{4 - (6 \cdot 0)}{- 2}$ $y = (4-(6*0))/-2$

$y = \frac{4}{- 2}$ $y = (4)/-2$

$y = - 2$ $y=-2$

This gives the first coordinate: $(0, - 2)$ $(0,-2)$

Repeat with a second number for the second coordinate and draw a line through the two points (only two points are needed).

graph{4=6x-2y [-4.505, 5.935, -2.75, 2.47]}

From the graph, we can see the point calculated, $(0, - 2)$ $(0,-2)$ lies on the graph.

Answer 2 · 2017-07-19T09:28:45

$see explanation$ $"see explanation"$

Explanation:

$one way is to find the x and y intercepts, that is where the$ $"one way is to find the x and y intercepts, that is where the"$
$line crosses the axes$ $"line crosses the axes"$

$∙ let x = 0, in the equation for y-intercept$ $• " let x = 0, in the equation for y-intercept"$

$∙ let y = 0, in the equation for x-intercept$ $• " let y = 0, in the equation for x-intercept"$

$x = 0 \to 0 - 2 y = 4 \to y = - 2 \leftarrow y-intercept$ $x=0to0-2y=4toy=-2larrcolor(red)" y-intercept"$

$y = 0 \to 6 x - 0 = 4 \to x = \frac{2}{3} \leftarrow x-intercept$ $y=0to6x-0=4tox=2/3larrcolor(red)" x-intercept"$

$plot these points and draw a straight line through them$ $"plot these points and draw a straight line through them"$
graph{3x-2 [-10, 10, -5, 5]}

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How do you graph $6 x - 2 y = 4$ $6x-2y=4$ by plotting points?

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Explanation:

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How do you graph $6 x - 2 y = 4$ $6x-2y=4$ by plotting points?