How do you graph #4y<=-6# on the coordinate plane?

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Answer 1 · 2017-09-05T19:53:50

See a solution process below:

Divide each side of the inequality by #color(red)(4)# to solve for #y# while keeping the inequality balanced:

#(4y)/color(red)(4) <= -6/color(red)(4)#

#(color(red)(cancel(color(black)(4)))y)/cancel(color(red)(4)) <= -6/4#

#y <= -3/2#

To graph this we will draw a horizontal line at #-3/2# on the vertical axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the below the line because the inequality operator also contains a "less than" clause:

graph{y<=-3/2 [-10, 10, -5, 5]}