How do you graph #3x-y<0#?

1 Answer
Meave60
May 10, 2015

Subtract 3x from both sides.

#3x-3x-y< 0-3x# =

#-y< -3x#

Multiply times #-1#.

#y>3x#

Determine two points on the line, temporarily changing the #># symbol to an #=# symbol.

If #x=0; y=3(0)=0#
Point = #(0,0)#

If #x=2; y=3*2=6#
Point = #(2,6)#

Plot the points on a graph and draw a dashed line (-----) through the points to indicate that the points on that line are not part of the inequality. Shade in the area above the line.

graph{y>3x [-14.24, 14.23, -7.12, 7.12]}

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