How do you graph # -3x-2y=-2#?

1 Answer
Meave60
Jun 21, 2017

Convert the given equation to slope intercept form, #y=mx+b.# Determine points on the line. Plot the points and draw a straight line through them.

Explanation:

Graph:

#-3x-2y=-2#

Solve for #y# to get the equation into slope intercept form: #y=mx+b#, where #m# is the slope and #b# is the y-intercept (the value of #y# when #x=0#).

Add #3x# to both sides of the equation.

#color(red)cancel(color(black)(3x))-color(red)cancel(color(black)(3x))-2y=3x-2#

Simplify.

#-2y=3x-2#

Divide both sides by #-2#.

#(color(red)cancel(color(black)(-2^1y)))/(color(red)cancel(color(black)(-2^1)))=(3x)/(-2)+(color(red)cancel(color(black)(-2^1))/color(red)cancel(color(black)(-2^1)))#

A negative number divided by another negative number gives a positive result.

#y=-3/2x+1#

Now you can determine several points on the line by choosing values for #x# and solving for #y#.

Points

#x=-2,##y=4#

#x=0,##y=1#

#x=2,##y=2#

Plot the points and draw a straight line through them.

graph{-3x-2y=-2 [-10, 10, -5, 5]}

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