How do you graph #-2x+3y>9#?

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Answer 1 · 2016-11-23T05:16:31

Graph #-2x+3y>9#

Convert the inequality to slope-intercept form, by solving for #y#.

Add #2x# to both sides.

#3y>2x+9#

Divide both sides by #3#.

#y>2/3x+9/3#

Simplify.

#y>2/3x+3#

Determine two points on the line.

#x=0:# #y=3#

#y=0:# #x=-9/2#

Plot the points.

Draw a dashed straight line to indicate that the line is not part of the inequality.

Shade in the area above the line.

graph{y>2/3x+3 [-10, 10, -5, 5]}