How do you give the six trigonometric function values of pi/3?

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How do you give the six trigonometric function values of pi/3?

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Answer 1 · 2017-08-06T19:26:57

$"see explanation"$

Explanation:

$"using the right triangle with angles and sides"$

$pi/2,pi/6,pi/3larrcolor(red)" angles"$

$1,sqrt3,2larrcolor(red)" sides"$

$"in relation to "cos(pi/3)$

$1" is adjacent ",sqrt3" is opposite",2" is hypotenuse"$

$•color(white)(x)cos(pi/3)=1/2$

$•color(white)(x)sec(pi/3)=1/cos(pi/3)=1/(1/2)=2$

$•color(white)(x)sin(pi/3)=sqrt3/2$

$•color(white)(x)csc(pi/3)=1/sin(pi/3)=1/(sqrt3/2)=2/sqrt3$

$•color(white)(x)tan(pi/3)=sin(pi/3)/(cos(pi/3))=(sqrt3/2)/(1/2)=sqrt3$

$•color(white)(x)cot(pi/3)=1/tan(pi/3)=1/sqrt3$

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How do you give the six trigonometric function values of pi/3?

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