How do you give the six trigonometric function values of -3pi?

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How do you give the six trigonometric function values of -3pi?

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Answer 1 · 2017-03-19T16:26:55

$sin(-3pi) = 0, cos(-3pi) = -1, tan(-3pi) = 0$
$csc(-3pi) = "undefined", sec(-3pi) = -1$ ,
$cot(-3pi) = "undefined"$

Explanation:

$-3pi$ has the same values as $pi$ due to the periodic nature of trigonometric functions. The negative sign means start at the $x-$ axis and go clockwise $3 * 180^@$ since $pi = 180^@$

$sin pi = sin(-3pi) = 0$

$cos pi = cos(-3pi) = -1$

$tan pi = (sin pi)/(cos pi) = 0/-1 = 0$

$csc pi = 1/(sin pi) = 1/0 = "undefined"$

$sec pi = 1/(cos pi) = 1/-1 = -1$

$cot pi = 1/(cot pi) = 1/0 = "undefined"$

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How do you give the six trigonometric function values of -3pi?

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