How do you give the six trigonometric function values of 19pi/3?

1 Answer
Nghi N.
Jun 2, 2016

Find 6 trig functions

Explanation:

Trig table and unit circle give -->
sin ((19pi)/3) = sin (pi/3 + (18pi)/3) = sin (pi/3 + 6pi) =
= sin (pi/3) = sqrt3/2
cos ((19pi)/3) = cos (pi/3) = 1/2
tan ((19pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3
cot ((19pi)/3) = 1/sqrt3 = sqrt3/3
sec ((19pi)/3) = 1/(cos) = 2
csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3

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