How do you foil #( x+8) (x - 8)#?

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Answer 1 · 2015-09-18T17:37:33

#=color(blue)(x^2-64#

The expression is :# (x+8)(x-8)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(x and x))#+

2)product of Outside terms:#(color(blue)(x and -8))#+

3)product of Inside terms:#(color(blue)(8 and x))#+

4)product of Last terms:#(color(blue)(8 and -8))#

1) #x *x=color(blue)(x^2) +#

2) #x * -8=-color(blue)(8x)+#

3) #8 * x = color(blue)(8x)+#

4) #8 *-8 = color(blue)(-64#

adding all the terms

#=color(blue)(x^2-8x +8x -64#
#=color(blue)(x^2-64#