How do you foil #(4x+5) (x+1)#?

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How do you foil #(4x+5) (x+1)#?

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Answer 1 · 2015-08-08T03:26:50

#(4x+5)(x+1)=4x^2+9x+5#

Explanation:

The FOIL method shows the order in which the terms of two binomials are to be multiplied. After multiplying the terms, combine like terms and add them.

#(4x+5)(x+1)# =

#4x*x+4x*1+5*x+5*1# =

#4x^2+9x+5#

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How do you foil #(4x+5) (x+1)#?

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