How do you finish the reaction: $B r_{2} (g) + K C l (a q) \to$ $Br_2(g) + KCl(aq) ->$ ?

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Answer 1 · 2018-05-12T07:30:24

There is no need.

Bromine is not a sufficiently strong oxidiser to displace chloride ions. This gives:

$sf(Br_(2(g))+KCl_((aq))rarr"no reaction")$

How do you finish the reaction: Br_2(g) + KCl(aq) ->Br2(g)+KCl(aq)→Br_2(g) + KCl(aq) ->?