How do you find two numbers whose sum is 49, if the greater number is 4 more than 8 times the smaller number?

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How do you find two numbers whose sum is 49, if the greater number is 4 more than 8 times the smaller number?

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Answer 1 · 2017-04-05T19:01:30

I got $44 and 5$

Explanation:

Call the numbers $x$ and $y$ , you get:
$x+y=49$
$x=8y+4$
substitute the second equation into the first:
$8y+4+y=49$
$9y=45$
$y=45/9=5$
so that:
$x=8*5+4=44$

Answer 2 · 2017-04-05T19:14:19

Write two equations and solve for one variable. Then substitute the value for the first variable to find the value for the second variable.

Explanation:

The first equation would be
$x + y = 49$

Where x = the first variable
Where y = the second variable.

The second equation would be

$y = 8x + 4$

where y = the larger number.

Put $8x + 4$ into the first equation in place of y this gives.

$x + 8x + 4 = 49$ solve the equation for x by combining terms

$9x + 4 = 49$ subtract 4 from both sides

$9x + 4 - 4 = 49 -4$ this gives

$9x = 45$ Divide both sides by 9 gives

$9x /9 = 45/9$ The answer is

$x= 5$ Now put 5 into one of the equation to find y

$y = 8(5) + 4$

$y = 44$

To check put the values into the first equation

$5 + 44 = 49$

x = 5 : y = 44

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How do you find two numbers whose sum is 49, if the greater number is 4 more than 8 times the smaller number?

2 Answers

Explanation:

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