How do you find two numbers whose difference is 4 and the difference of their square is 88?

1 Answer
Leland Adriano Alejandro
Mar 13, 2016

x=13
y=9

Explanation:

How do you find two numbers whose difference is 4 and the difference of their square is 88?

Solution:

let x=the larger number
let y=the smaller number

x-y=4first equation
x^2-y^2=88second equation

Substitute the first in to the second equation

x^2-y^2=88second equation
(y+4)^2-y^2=88
y^2+8y+16-y^2=88
8y=88-16
8y=72
y=9

Solve for x using first equation

x-y=4first equation
x-9=4
x=9+4
x=13

God bless... I hope the explanation is useful.

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