How do you find three consecutive odd integers, whose sum is 57?

Question

23436 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-21T10:46:06

Let the first and the smallest integer be $x-2$

Then... the second integer will be $x$

Then.... the third integer will be $x+2$

Now... their sum is $57$

$xcancel(-2)+x+x+cancel2=57$

You get

$3x=57$

$x=57/3$

$color(red)(x=19$ ( that's the second integer)

First integer
$x-2=19-2$

$color(red)(x-2=17$

Third integer
$x+2=19+2$

$color(red)(x+2=21$

Answer 2 · 2018-05-21T10:46:45

Three consecutive odd integers are $17,19,21$

Let the three consecutive odd integers are $2 x-1, 2 x+1,2 x+3$

Then , $2 x-1+2 x+1+2 x+3=57 or 6 x+3=57$ or

$6 x =54 :. x=9 , 2 x - 1= 17 , 2 x +1=19 , 2 x+3= 21$

Three consecutive odd integers are $17,19,21$ [Ans]