How do you find three consecutive even integers if the sum of the first two minus the third is 16?

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Answer 1 · 2016-03-13T00:17:51

Express the condition in symbolic form and solve to find the three integers are:

$18, 20, 22$

Let the smallest of the three consecutive integers be $n$ . Then the other two are $n+2$ and $n+4$ .

The condition in the question can be expressed:

$n + (n+2) - (n+4) = 16$

That simplifies to :

$n - 2 = 16$

Hence $n = 16+2 = 18$

So the three integers are $18$ , $20$ , $22$ .