How do you find the zeros of the function f(x)=(3x^2-18x+24)/(x-6)?

1 Answer
Jun 5, 2017

x=2,x=4

Explanation:

"zeros are the values of x that make f(x) equal zero"

rArr(3x^2-18x+24)/(x-6)=0

"the numerator therefore must equal zero"

"solve " 3x^2-18x+24=0" for zeros"

3(x^2-6x+8)=0larr" common factor of 3"

3(x-2)(x-4)=0

"equate each factor to zero"

x-2=0tox=2

x-4=0tox=4