How do you find the zeros of the function f(x)=(3x^2-18x+24)/(x-6)?
1 Answer
Jun 5, 2017
Explanation:
"zeros are the values of x that make f(x) equal zero"
rArr(3x^2-18x+24)/(x-6)=0
"the numerator therefore must equal zero"
"solve " 3x^2-18x+24=0" for zeros"
3(x^2-6x+8)=0larr" common factor of 3"
3(x-2)(x-4)=0
"equate each factor to zero"
x-2=0tox=2
x-4=0tox=4