How do you find the zero of #f(x)=3x+1#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer seol Nov 13, 2016 #x=-1/3# Explanation: The zero(s) of a function #f(x)# are found when you set the function equivalent to 0. #f(x)=3x+1# #0=3x+1# #-1=3x# #-1/3=x# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 7095 views around the world You can reuse this answer Creative Commons License