How do you find the z score for which 12% of the distribution's area lies between z and -z?

1 Answer
Miles A.
May 17, 2015

Firstly we will find the area of which is not between #z# and #-z#

So we do the sum of #100% - 12% = 88%# which does not lie between #z# and #-z#

we know that our standard normal distribution is symmetric, so we would like to equally distribute the area that is not between #z# and #-z# on either side.

thus on each side of our area, we have #(88%)/2 = 44%#

and we will find in our table that #z=0.15# and #-z=-0.15#

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