How do you find the vertical, horizontal or slant asymptotes for #(x+2) / (2x^2)#?

1 Answer
turksvids
Dec 28, 2017

Horizontal: #y=0#
Vertical: #x=0#

Explanation:

Since the degree of the polynomial in the denominator is greater than the degree of the polynomial in the numerator, the horizontal asymptote is #y=0#.

The denominator is equal to #0# when #x=0# and there is no factor in the numerator to cancel that out, so #x=0# is the vertical asymptote of the given function.

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