How do you find the values of w, x, y, and z given #-2[(w+5, x-z), (3y, 8)]=[(-16, -4), (6, 2x+8z)]#?

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Answer 1 · 2016-12-29T08:09:30

#w=3#

#y=-1#

#z=-2#

#x=0#

First you can divide both of sides by -2 an then you can get the following four relations:

1) #w+5=8#;

2) #3y=-3#;

3) #x-z=2#;

4) #8=-x-4z#

Then

1) #w=3#

2) #y=-1#

By summing 3) and 4), you get:

#cancelx-zcancel(-x)-4z=2+8#

#-5z=10#

3) #z=-2#

4) #x=z+2=0#