How do you find the values of theta given sectheta=sqrt2?

1 Answer
Binayaka C.
Feb 11, 2017

General solution : theta = (2 n pi + pi/4) , theta = (2 n pi + (7pi)/4) , where n is an integer [n = 0, 1, 2,3 ,.........]

Explanation:

sec theta = sqrt 2 :. cos theta = 1/sqrt 2 ; cos 45^0 = 1/sqrt 2 , cos (360-45) =cos 315= 1/sqrt 2 :. theta = 45^0 (pi/4), 315^0((7pi)/4) Note: cos theta is positive in 1st and last quadrant.

General solution : theta = (2 n pi + pi/4) , theta = (2 n pi + (7pi)/4) where n is an integer [n = 0, 1, 2,3 ,.........] [Ans]

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