How do you find the values of #theta# given #costheta=sqrt2/2#?

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How do you find the values of #theta# given #costheta=sqrt2/2#?

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Answer 1 · 2018-02-12T01:53:34

#t = pi/4 + 2kpi#
#t = (7pi)/4 + 2kpi#

Explanation:

#cos t = sqrt2/2#
Trig table and unit circle give 2 solutions -->
#t = +- pi/4#
Note that #t = (7pi)/4# is co-terminal to #t = (-pi/4)#.
Therefor the 2 answers are:
#t = pi/4 + 2kpi#, and
#t = (7pi)/4 + 2kpi#

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How do you find the values of #theta# given #costheta=sqrt2/2#?

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