How do you find the values of the six trigonometric functions of $t= (16 pi) / 3$ ?

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Answer 1 · 2015-06-04T22:43:44

On the trig unit circle:
$sin t = sin ((16pi)/3) = sin ((4pi)/3 + 4pi) = sin ((4p)/3) = - sin ((pi)/3) = -(sqrt3)/2$

$cos t = cos ((4pi)/3 + 4pi) = cos ((4pi)/3) = -cos ((pi)/3) = -1/2$

$tan t = -sqrt3$

$cot t = -(sqrt3)/3$

sec t = 1/cos t =

csct =1/sin t =

How do you find the values of the six trigonometric functions of t= (16 pi) / 3t= (16 pi) / 3?