How do you find the value of $sin^2(225^circ)$ ?

Question

3740 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-21T08:35:24

$sin^2 225^o=1/2$

As $sin(180+A)=-sinA$

$sin225^o=sin(180^o+45^o)=-sin45^o$

but $sin45^o=1/sqrt2$ and hence $sin225^o=-1/sqrt2$

Hence, $sin^2 225^o=(-1/sqrt2)^2=1/2$

How do you find the value of sin^2(225^circ)sin^2(225^circ)?