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How do you find the value of #sin^2(225^circ)#?

1 Answer

Shwetank Mauria

Nov 21, 2016

#sin^2 225^o=1/2#

Explanation:

As #sin(180+A)=-sinA#

#sin225^o=sin(180^o+45^o)=-sin45^o#

but #sin45^o=1/sqrt2# and hence #sin225^o=-1/sqrt2#

Hence, #sin^2 225^o=(-1/sqrt2)^2=1/2#

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