Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the value of #sin^2(225^circ)#?

1 Answer

Shwetank Mauria

Nov 21, 2016

#sin^2 225^o=1/2#

Explanation:

As #sin(180+A)=-sinA#

#sin225^o=sin(180^o+45^o)=-sin45^o#

but #sin45^o=1/sqrt2# and hence #sin225^o=-1/sqrt2#

Hence, #sin^2 225^o=(-1/sqrt2)^2=1/2#

Related questions

See all questions in Trigonometric Functions of Any Angle

Impact of this question

3507 views around the world

You can reuse this answer
Creative Commons License