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How do you find the value of sec (2pi/3)?

1 Answer

Jun 29, 2016

$sec(2pi/3)=sec(pi-pi/3)=-sec(pi/3)=-1/cos(pi/3)=-1/(1/2)=-2$

Explanation:

$sec(2pi/3)=sec(pi-pi/3)=-sec(pi/3)=-1/cos(pi/3)=-1/(1/2)=-2$

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