How do you find the value of $sec^2(225^circ)$ ?

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Answer 1 · 2017-04-28T11:37:55

$1/4$

$sec^2(225 ^circ) = sec^2(2xx90 + 45)^circ$

$rArr [-sec45^circ]^2$

Note:- [ $225^circ$ is in 3rd Quadrant where only tan & cot positive.]

$rArr [-1/(sqrt 2)]^2$

$rArr 1/4$

How do you find the value of sec^2(225^circ)sec^2(225^circ)?