How do you find the value of $cot (pi/2)$ ?

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Answer 1 · 2015-06-09T06:15:32

You can use two trig identities: $cotx = 1/tanx$ and $tanx = (sinx)/(cosx)$ .

$cotx = 1/tanx = cosx/sinx$

$pi/2 "rad" = 90^o$

$sin 90^o = 1$
$cos 90^o = -1$

$cot90^o = (cos90^o)/(sin90^o) = (-1)/(1) = -1$

How do you find the value of cot (pi/2)cot (pi/2)?