How do you find the value of $cos (\frac{14 π}{3})$ $cos ((14pi)/3)$ ?

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How do you find the value of $cos (\frac{14 π}{3})$ $cos ((14pi)/3)$ ?

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Answer 1 · 2016-08-01T03:44:58

$- \frac{1}{2}$ $- 1/2$

Explanation:

Trig table and unit circle -->
$cos (\frac{14 π}{3}) = cos (\frac{2 π}{3} + \frac{12 π}{3}) = cos (\frac{2 π}{3} + 4 π) =$ $cos ((14pi)/3) = cos ((2pi)/3+ (12pi)/3) = cos ((2pi)/3 + 4pi) =$
$= cos (\frac{2 π}{3}) = - \frac{1}{2}$ $= cos ((2pi)/3) = -1/2$

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How do you find the value of $cos (\frac{14 π}{3})$ $cos ((14pi)/3)$ ?

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How do you find the value of $cos (\frac{14 π}{3})$ $cos ((14pi)/3)$ ?