How do you find the value of cos ((13pi)/12)? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer P dilip_k May 7, 2016 =-1/2sqrt(1/2(sqrt3+1)) Explanation: cos((13pi)/12)=cos(pi+pi/12)=-cos((pi)/12) =-sqrt(1/2(1+cos(2*pi/12)))=-sqrt(1/2(1+cos(pi/6))) =-sqrt(1/2(1+sqrt3/2))=-sqrt(1/8(4+2*sqrt3)) =-sqrt(1/(2*2^2)((sqrt3)^2+2*sqrt3*1+1^2)) =-sqrt(1/(2*2^2)(sqrt3+1)^2) =-1/2sqrt(1/2(sqrt3+1)) Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 2521 views around the world You can reuse this answer Creative Commons License