How do you find the value of # cos ((13pi)/12)#?

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How do you find the value of # cos ((13pi)/12)#?

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Answer 1 · 2016-05-07T04:35:45

#=-1/2sqrt(1/2(sqrt3+1))#

Explanation:

#cos((13pi)/12)=cos(pi+pi/12)=-cos((pi)/12)#
#=-sqrt(1/2(1+cos(2*pi/12)))=-sqrt(1/2(1+cos(pi/6)))#
#=-sqrt(1/2(1+sqrt3/2))=-sqrt(1/8(4+2*sqrt3))#
#=-sqrt(1/(2*2^2)((sqrt3)^2+2*sqrt3*1+1^2))#
#=-sqrt(1/(2*2^2)(sqrt3+1)^2)#

#=-1/2sqrt(1/2(sqrt3+1))#

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How do you find the value of # cos ((13pi)/12)#?

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