How do you find the value of a if #2i# is a root of #z^3-2z^2i+az-32i=0#? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Konstantinos Michailidis Aug 12, 2016 Hence it is a root just replace the value of #z# with #2i# so we get #(2i)^3-2(2i)^2i+a(2i)-32i=0=> -8i+8i+2ia-32i=0=> 2i(a-16)=0=>a=16# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1851 views around the world You can reuse this answer Creative Commons License