How do you find the value of a if 2i is a root of z^3-2z^2i+az-32i=0? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Konstantinos Michailidis Aug 12, 2016 Hence it is a root just replace the value of z with 2i so we get (2i)^3-2(2i)^2i+a(2i)-32i=0=> -8i+8i+2ia-32i=0=> 2i(a-16)=0=>a=16 Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression 3x-x+4? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression 2x+1 for x=1? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1707 views around the world You can reuse this answer Creative Commons License