How do you find the value of #1/5 - ((20(81div9))/25)#? Prealgebra Arithmetic and Completing Problems Order of Operations 1 Answer Rajinder S. Oct 20, 2016 #-7# Explanation: =# 1/5 - (20xx color(red)((81 -: 9))/ 25) # Solve the inner bracket, # color(blue)(81 -: 9 = 9) #, so =# 1/5 - (((20xxcolor(blue)9))/ 25) # Solve #color(brown)(20xx 9= 180)# =#5/25- 180/25 # =#(5-180)/25 # = #-175/25 # = #-7# Answer link Related questions What is #5-3*(-2) + |-3|#? What is #(3 * 10)^2 -: 5 - 4#? What is #2+2(2)^2(5)+ 8#? What is #14.3 * 2.1 * 8.9#? What is #8+(8+8-:4)+5^2#? How do you use PEMDAS to simplify #3 times 2 - (8+1) #? How do you simplify #3^4+2^3+8(4xx2-5) #? How do you simplify #4times3^2+3times4^2+2(3times4)^2#? How do you solve #30-5(4^2-8รท4-5*2)#? What is #7-3(-8-2) + 6 -:2#? See all questions in Order of Operations Impact of this question 1649 views around the world You can reuse this answer Creative Commons License