How do you find the unit vector in the direction of $vecu = (2,1,-3)$ ?

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Answer 1 · 2018-03-15T21:54:19

The unit vector in the direction of any given vector is the vector divided by its magnitude:

$hatu = vecu/|vecu|$

Given $vecu = (2,1,-3)$

$|vecu| = sqrt(2^2+1^2+ (-3)^2)$

$|vecu| = sqrt14$

$hatu= 1/sqrt14(2,1,-3)$

$hatu= sqrt14/14(2,1,-3)$

$hatu= (2sqrt14/14,sqrt14/14,-3sqrt14/14)$

How do you find the unit vector in the direction of vecu = (2,1,-3)vecu = (2,1,-3)?