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How do you find the unit vector in the direction of the given vector u=<-2,2>?

1 Answer

Jan 19, 2017

#=-i/(sqrt2)+j/(sqrt2) or<-1/(sqrt2),1/(sqrt2)>#

Explanation:

#|u| =sqrt((-2)^2+2^2)#
#|u| =sqrt(4+4)#
#|u| =sqrt(8)#
#|u| =sqrt(4*2)#
#|u| =2sqrt(2)#

Unit Vector #=1/|u|(-2i+2j)#
#=1/(2sqrt2)(-2i+2j)#

#=1/(cancel2sqrt2)*cancel2(-i+j)#

#=1/(sqrt2)(-i+j)#

#=-i/(sqrt2)+j/(sqrt2)#

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