How do you find the standard form of the following equation $Y = {(x + 3)}^{2} + 1$ $Y=(x+3)^2+1$ ?

Question

How do you find the standard form of the following equation $Y = {(x + 3)}^{2} + 1$ $Y=(x+3)^2+1$ ?

1 Answer

Impact of this question

4835 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-11T15:28:11

Standard form is $y = x^{2} + 6 x + 10$ $y=x^2+6x+10$

Explanation:

$y = {(x + 3)}^{2} + 1$ $y=(x+3)^2+1$

Multiply, or FOIL, the term being squared in the parentheses:
$y = (x + 3) (x + 3) + 1$ $y=(x+3)(x+3)+1$
$y = x^{2} + 3 x + 3 x + 9 + 1$ $y=x^2+3x+3x+9+1$

Combine like terms:
$y = x^{2} + 6 x + 10$ $y=x^2+6x+10$

Science

Math

Humanities

... and beyond

How do you find the standard form of the following equation $Y = {(x + 3)}^{2} + 1$ $Y=(x+3)^2+1$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the standard form of the following equation Y=(x+3)^2+1Y=(x+3)2+1Y=(x+3)^2+1?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the standard form of the following equation $Y = {(x + 3)}^{2} + 1$ $Y=(x+3)^2+1$ ?