How do you find the slope of the line passing through (6,11), (6,-5)?

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How do you find the slope of the line passing through (6,11), (6,-5)?

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Answer 1 · 2018-06-21T21:40:34

$\infty$ $\infty$

Explanation:

Slope of line passing through the points $(6, 11) \equiv (x_{1}, y_{1})$ $(6, 11)\equiv(x_1, y_1)$ & $(6, - 5) \equiv (x_{2}, y_{2})$ $(6, -5)\equiv(x_2, y_2)$
$= \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $=\frac{y_2-y_1}{x_2-x_1}$
$= \frac{- 5 - 11}{6 - 6}$ $=\frac{-5-11}{6-6}$
$= \infty$ $=\infty$
The line joining the given points $(6, 11)$ $(6, 11)$ & $(6, - 5)$ $(6, -5)$ is vertical having infinite slope

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How do you find the slope of the line passing through (6,11), (6,-5)?

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