How do you find the slope of (4,-5),(-1,-5)?

2 Answers
Apr 21, 2017

The slope is #-9/4#

Explanation:

Using the basis that slope is #(rise)/(run)#, or change in #x# over change in #y#, we cand find the slope of a line based on two points, like so:

#(y_2-y_1)/(x_2-x_1)#

#(-5-4)/(-1--5)#

#(-9)/(4)#

The slope is #-9/4#

Apr 21, 2017

#"slope "=0#

Explanation:

To calculate the slope use the #color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1),(x_2,y_2)" 2 coordinate points"#

#"the 2 points here are " (4,-5)" and " (-1,-5)#

#"let " (x_1,y_1)=(4,-5)" and " (x_2,y_2)=(-1,-5)#

#rArrm=(-5-(-5))/(-1-4)=0/(-5)=0#

A slope of zero indicates that the line is horizontal, parallel to the x-axis and passes through all points with the same y-coordinate, in this case y = - 5

#"the equation of this line is therefore " y=-5#
graph{y-0.001x+5=0 [-10, 10, -5, 5]}