How do you find the slope given #3y= x -1/2#?

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Answer 1 · 2017-09-06T12:20:43

See a solution process below:

First, we can put the equation into slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#3y = x - 1/2#

#(3y)/color(red)(3) = (x - 1/2)/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = x/color(red)(3) - (1/2)/color(red)(3)#

#y = x/3 - 1/6#

#y = color(red)(1/3)x - color(blue)(1/6)#

Therefore, the slope of the line represented by this equation is:

#color(red)(m = 1/3)#