How do you find the slope for #5x-2y = 10#?

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Answer 1 · 2015-05-17T21:05:13

To find the slope, rearrange into the standard form #y=mx+c# where #m# is the slope and #c# the intercept as follows:

First add #2y# to both sides to get:

#5x=10+2y#

Next subtract #10# from both sides to get:

#5x-10=2y#

Now divide both sides by 2 to get:

#(5/2)x-5 = y#

In other words: #y = (5/2)x-5#.

Comparing with #y=mx+c#, the slope #m# is #5/2 = 2.5# (and the intercept #c# is #-5#).