How do you find the slope for (-3,-3); (0,0)?

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Answer 1 · 2015-05-14T01:45:49

The slope, $m$ $m$ , of the line that passes through points $(- 3, - 3)$ $(-3,-3)$ and $(0, 0)$ $(0,0)$ is $1$ $1$ .

The formula for finding the slope, $m$ $m$ , of a line from two points on the line is:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

Point 1 = $(- 3, - 3)$ $(-3,-3)$
$x_{1} = - 3$ $x_1=-3$ y_1=-3

Point 2 = $(0, 0)$ $(0,0)$
$x_{2} = 0$ $x_2=0$
$y_{2} = 0$ $y_2=0$

Solve for slope.

$m=(0-(-3))/(0-(-3))=cancel3/cancel3=1$ =

$m=1$