How do you find the six trigonometric functions of $(-7pi)/4$ degrees?

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Answer 1 · 2015-05-07T16:24:40

Trig unit circle:

$sin (-7pi/4) = sin (pi/4 - 2pi) = sin (pi/4) = (sqr2)/2$ (trig table)

$cos (-7pi/4) = cos (pi/4 - 2pi) = cos (pi/4) = (sqr2)/2$ (trig table)

$tan (-7pi/4) = tan (pi/4) = ((sqr2)/2).(2/(sqr2)) = 1$

$cot (-7pi/4) = 1$

$sec (-7pi/4) = 2/(sqr2) = (2.sqr2)/2$

$csc (-7pi/4) = (2.sqr2)/2$

How do you find the six trigonometric functions of (-7pi)/4(-7pi)/4 degrees?