How do you find the six trigonometric functions of $\frac{5 π}{3}$ $(5pi)/3$ degrees?

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How do you find the six trigonometric functions of $\frac{5 π}{3}$ $(5pi)/3$ degrees?

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Answer 1 · 2015-05-14T02:18:05

Use the trig unit circle as proof.

$sin (\frac{5 π}{3}) = sin (- \frac{π}{3} + 2 π) = - sin (\frac{π}{3}) = \frac{- s q r 3}{2}$ $sin ((5pi)/3) = sin (-pi/3 + 2pi) = -sin (pi/3) = (-sqr3)/2$

$cos (\frac{5 π}{3}) = cos (- \frac{π}{3} + 2 π) = cos (\frac{π}{3}) = \frac{1}{2}$ $cos ((5pi)/3) = cos (-pi/3 + 2pi) = cos (pi/3) = 1/2$

$tan (\frac{5 π}{3}) = (- s q r \frac{3}{2}) . (\frac{2}{1}) = - s q r 3$ $tan ((5pi)/3) = (-sqr3/2).(2/1) = -sqr3$

$cot (\frac{5 π}{3}) = \frac{- s q r 3}{3}$ $cot ((5pi)/3) = (-sqr3)/3$

$sec (\frac{5 π}{3}) = 2$ $sec ((5pi)/3) = 2$

$csc (\frac{5 π}{3}) = (\frac{- 2 s q r 3}{3})$ $csc ((5pi)/3) = ((-2sqr3)/3)$

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How do you find the six trigonometric functions of $\frac{5 π}{3}$ $(5pi)/3$ degrees?

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