How do you find the six trigonometric functions of 300 degrees?

Question

43778 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-25T21:40:15

Use the trig unit circle as proof.

$sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 =$ $(-sqrt3)/2$

$cos 300 = cos (-60 + 300) = cos 60 = 1/2$

$tan 300 = (-sqrt3)/2 : (1/2) = -sqrt3$

$cot 300 = 1/(sqrt3) = (-sqrt3)/3$

$sec 300 = 1/cos 300 = -2/(sqrt3) = (-2sqrt3)/3$

$csc 300 = 1/sin 300 = 2$