How do you find the six trigonometric functions of 300 degrees?

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Answer 1 · 2015-05-25T21:40:15

Use the trig unit circle as proof.

#sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 =## (-sqrt3)/2#

#cos 300 = cos (-60 + 300) = cos 60 = 1/2#

#tan 300 = (-sqrt3)/2 : (1/2) = -sqrt3#

#cot 300 = 1/(sqrt3) = (-sqrt3)/3#

#sec 300 = 1/cos 300 = -2/(sqrt3) = (-2sqrt3)/3#

#csc 300 = 1/sin 300 = 2#